(x+4)^2=2x^2+18x+37

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Solution for (x+4)^2=2x^2+18x+37 equation: 



(x+4)^2=2x^2+18x+37

We move all terms to the left:

(x+4)^2-(2x^2+18x+37)=0

We get rid of parentheses

-2x^2+(x+4)^2-18x-37=0

We add all the numbers together, and all the variables

-2x^2-18x+(x+4)^2-37=0

We move all terms containing x to the left, all other terms to the right

-2x^2-18x+(x+4)^2=37

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